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    Author Topic: Bitcoin puzzle transaction ~32 BTC prize to who solves it  (Read 325154 times)

    • Evillo
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    January 13, 2023, 03:20:03 PM
     #2001
    Quote from: james5000 on January 11, 2023, 03:36:14 PM
    https://github.com/Jamerson1000/btc-puzzle  Wink

    Can i ask what did you mean by "bitcrack doesn't work when workspace is larger than 999.999" ?

  • zahid888
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    January 16, 2023, 08:50:52 PM
     #2002
    Quote from: zahid888 on July 25, 2021, 09:21:39 AM
    @Andzhig And if we increase one more character of address 16jY7qLJn & 'x' then most binaries are started from '111'

    few examples - 

    16jY7qLJnxLQQRYPX5BLuCtcBs6tvXz8BE   1110000000100110101001101101010100100011010011001000100000110110000   7013536A91A6441B0
    16jY7qLJnX9uchnyf26t3QJnsUf78Xdikb   1110010000101000111010000001111110010000001011001101111011100000   E428E81F902CDEE0
    16jY7qLJnX9eX8j612s8fnbn6uzR48xjua   1110100000001101111010110011001110101001011001111010000010001111   E80DEB33A967A08F
    16jY7qLJnx2EZZumnYFke3GutCrRnHKs1M   111010110100110101001101101010111010101000110011101011001010110000   3AD3536AEA8CEB2B0
    16jY7qLJnx2ixrxCnTLSraerkgyB3YYAiT   1110110111111001110011010110000000110101011011011100110000011001   EDF9CD60356DCC19
    16jY7qLJnxHBp3dqwV2kzYq1LucfZzgxsH   1110111010111001101010110011001101001101111100100111011100001101   EEB9AB334DF2770D
    16jY7qLJnX2cZXJ78wV1ef42e7cLAZJ1Vn   1111111000101000011001011100011011011011111111101100001110000011   FE2865C6DBFEC383
    16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN   1111011100000101000111110010011110110000100100010001001011010100 F7051F27B09112D4


    Could this also be some logic?

    can you shed more light on this issue
    1BGvwggxfCaHGykKrVXX7fk8GYaLQpeixA

  • bikkesbakker
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    January 17, 2023, 05:01:30 PM
     #2003
    Quote from: BitDominator00 on April 13, 2022, 07:21:43 AM
    Quote from: bikkesbakker on April 13, 2022, 03:42:52 AM
    Quote from: zahid888 on April 12, 2022, 02:59:09 AM
    https://i.imgur.com/VGuN8R1.png

    I was checking exatly the same the other day, hi everyone im new into this puzzle, and im obsessed with it. Spend hours and hours looking for a pattern, and there is no pattern as the "owner" mentioned it but i was looking for the already found keys and i think i found something.

    If someone is brute forcing this, you need to start from eb851eb851eb8000 to ffffffffffffffff, thats why this is not still be found, the hex is almost at the end of the range. Im bruteforcing this from feb851eb851eb800 to ffffffffffffffff at 25 MKey/s (yes is a little slow but is honest work Tongue ) and i will be checking from the back after finish a range.

    I hope this helps anyone, and if i do please share something as i will share to 2 users of this forum (if i find the key) who gives me the idea Smiley


    Regards from AR and sorry about my english.

    based on what you say to start from that point of the range ?

    so i was right, and i think where to start from for puzzle 66, i think i found a pattern. Ive also got a 1080 at a good price so im searching at 240 MKeys/s

  • WanderingPhilospher
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    January 17, 2023, 05:53:57 PM
     #2004
    Quote from: bikkesbakker on January 17, 2023, 05:01:30 PM
    Quote from: BitDominator00 on April 13, 2022, 07:21:43 AM
    Quote from: bikkesbakker on April 13, 2022, 03:42:52 AM
    Quote from: zahid888 on April 12, 2022, 02:59:09 AM


    I was checking exatly the same the other day, hi everyone im new into this puzzle, and im obsessed with it. Spend hours and hours looking for a pattern, and there is no pattern as the "owner" mentioned it but i was looking for the already found keys and i think i found something.

    If someone is brute forcing this, you need to start from eb851eb851eb8000 to ffffffffffffffff, thats why this is not still be found, the hex is almost at the end of the range. Im bruteforcing this from feb851eb851eb800 to ffffffffffffffff at 25 MKey/s (yes is a little slow but is honest work Tongue ) and i will be checking from the back after finish a range.

    I hope this helps anyone, and if i do please share something as i will share to 2 users of this forum (if i find the key) who gives me the idea Smiley


    Regards from AR and sorry about my english.

    based on what you say to start from that point of the range ?

    so i was right, and i think where to start from for puzzle 66, i think i found a pattern. Ive also got a 1080 at a good price so im searching at 240 MKeys/s
    Lol...okay, so where to start for puzzle 66? 20000000000000000?

  • citb0in
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    January 17, 2023, 06:08:16 PM
     #2005
    it is completely pointless to "guess" or "estimate" a range since the author of the puzzle has already made a clear statement about it --> there IS NO PATTERN  Cool
    However good luck to everybody!
    Some signs are invisible, some paths are hidden - but those who see, know what to do. Follow the trail - Follow your intuition - [bc1qqnrjshpjpypepxvuagatsqqemnyetsmvzqnafh]

  • WanderingPhilospher
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    January 17, 2023, 07:06:45 PM
     #2006
    Quote
    well you saying this stupid thing i know you didnt read my message at all, puzzle 64 start from 8000000000000000 to ffffffffffffffff i say start from eb851eb851eb8000 so yea, i save a lot of time from 8000000000000000 to Eb and the hex started at f7, so go F yourself we are not here making funny or stupid commenting things, so F you and i keep this pattern to myself, Good luck Smiley
    Lol...I merely said it because you had a 1 in 8 chance of guessing correctly and you claim you have a good start for #66 but do not share, why? Maybe because you will be wrong? I have trillions of keys checked in each sub 48 bit range; so if you know the first 1 to 5 starting characters for #66, tell us, and I will tell you if it's been checked already.

  • citb0in
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    January 17, 2023, 07:13:25 PM
     #2007
    Quote from: bikkesbakker on January 17, 2023, 06:09:48 PM
    yes, there is, if you really think automated random created things are really random, then think twice.

    Ok, I will ... hold on a second ... finished.

    Now, please tell me what the weather in South Florida will be on 2024/Feb/29 at 02:19 PM.
    Some signs are invisible, some paths are hidden - but those who see, know what to do. Follow the trail - Follow your intuition - [bc1qqnrjshpjpypepxvuagatsqqemnyetsmvzqnafh]

  • WanderingPhilospher
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    January 17, 2023, 08:14:42 PM
     #2008
    Quote from: citb0in on January 17, 2023, 07:13:25 PM
    Quote from: bikkesbakker on January 17, 2023, 06:09:48 PM
    yes, there is, if you really think automated random created things are really random, then think twice.

    Ok, I will ... hold on a second ... finished.

    Now, please tell me what the weather in South Florida will be on 2024/Feb/29 at 02:19 PM.
    Warmer than what it will be where I am lol...

  • stefanuccio
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    January 18, 2023, 03:23:35 PM
     #2009
    Hi everybody,
    maybe someone already noticed.. not sure
    PUZZLE 66.....
    Looking at address "https://privatekeys.pw/address/bitcoin/13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so" I just realized that there is a DOGE coin address  with A BALANCE that has the SAME private key !!!
    Does this means that the owner of DOGE address could theoretically take the Bitcoin in puzzle#66 ??
    .. in addition...
    I am really suprised of the probability that this can happen.... same key that have a Bitcoin and DOGE addresses both with balance ? it could be the puzzle owner DOGE account ? or maybe that key is derived from some simple schema ??
    what do you think ?
    I tried to search in google for that DOGE address but no relevant info found.

  • albert0bsd
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    January 18, 2023, 04:53:53 PM
    Merited by nc50lc (1)
     #2010
    The hash rmd160 is the same for almost all chains, yes you can derive the doge address from it the only change is the prefix byte.

  • nc50lc
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    January 19, 2023, 07:47:35 AM
     #2011
    Quote from: stefanuccio on January 18, 2023, 03:23:35 PM
    -snip-
    I am really suprised of the probability that this can happen.... same key that have a Bitcoin and DOGE addresses both with balance ? it could be the puzzle owner DOGE account ? or maybe that key is derived from some simple schema ??
    what do you think ?
    If you see any funded address, that doesn't mean that someone knows its private key.
    That Dogecoin address is one example, someone just derived the dogecoin address from p66's address then sent dogecoins to it.

    In your link, see that "Public Key Hash (Hash 160)" below the address?
    That's basically the address when decoded with base58 without the network bytes and checksum.
    Simply add any altcoin's network bytes, etc. and encode it with base58check to get the equivalent altcoin address.

  • citb0in
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    January 19, 2023, 08:36:02 AM
    Last edit: January 19, 2023, 01:48:32 PM by citb0in
    Merited by nc50lc (1), saxydev (1)
     #2012
    Here's an example for python. The program takes the hash160 value as the first argument of the command line call. It then uses this value to generate both the Bitcoin and Dogecoin addresses by using the same value with different version bytes and Base58Check encoding rules.

    Code:
    #/usr/bin/env python3
    # ./hash160_to_address.py <hash160>
    # by citb0in, 2023/Jan/19
    import sys
    import hashlib
    import base58

    # hash160
    h = sys.argv[1]

    # version byte (for Bitcoin "00", for Dogecoin it's "1E")
    version_btc = b"\x00"
    version_doge = b"\x1E"

    # hash160 + version byte
    h_btc = version_btc + bytes.fromhex(h)
    h_doge = version_doge + bytes.fromhex(h)

    # double-sha256
    r_btc = hashlib.sha256(h_btc).digest()
    r_doge = hashlib.sha256(h_doge).digest()
    r_btc = hashlib.sha256(r_btc).digest()
    r_doge = hashlib.sha256(r_doge).digest()

    # first 4 bytes of sha256(sha256)
    checksum_btc = r_btc[:4]
    checksum_doge = r_doge[:4]

    # hash160 + version byte + checksum
    address_btc = h_btc + checksum_btc
    address_doge = h_doge + checksum_doge

    # base58 conversion to get the address
    address_btc = base58.b58encode(address_btc)
    address_doge = base58.b58encode(address_doge)

    print(f"\n\nHash160 = {h}")
    print(f"Bitcoin (BTC) address = {address_btc.decode()}")
    print(f"Dogecoin (DOGE) address = {address_doge.decode()}")

    Code:
    $ python3 hash160_to_address.py 20d45a6a762535700ce9e0b216e31994335db8a5
    Quote
    Hash160 = 20d45a6a762535700ce9e0b216e31994335db8a5
    Bitcoin (BTC) address = 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so
    Dogecoin (DOGE) address = D88gYxMEoumtZSJAC9mwa2EWfm6g3uocon

    Now for additional example take the hash160 of puzzle #67 which is 739437bb3dd6d1983e66629c5f08c70e52769371 and calculate the DOGE address:
    Code:
    $ python3 hash160_to_address.py 739437bb3dd6d1983e66629c5f08c70e52769371
    Quote
    Hash160 = 739437bb3dd6d1983e66629c5f08c70e52769371
    Bitcoin (BTC) address = 1BY8GQbnueYofwSuFAT3USAhGjPrkxDdW9
    Dogecoin (DOGE) address = DFgDofYSD4T6CwdVykSc2CLJ9s8A6Bqt97

    If you or someone else send some coins to DFgDofYSD4T6CwdVykSc2CLJ9s8A6Bqt97 you will see the same effect.

    EDIT:
    You can find an extended version of this tool on my github repository. It will also show the native segwit (bech32) address of the hash. I have added also Litecoin as an additional example because I know that Litecoin supports bech32, too. I don't give a **** about shitcoins, it should just serve as programming example to see how this works.

    Code:
    $ python3 ./hash160_to_coin_addresses.py 20d45a6a762535700ce9e0b216e31994335db8a5
    Quote
    Hash160 = 20d45a6a762535700ce9e0b216e31994335db8a5
    Bitcoin (BTC) address = 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so
    Bitcoin (BTC) bech32 address = bc1qyr2956nky56hqr8fuzepdccejse4mw994lyftn
    Dogecoin (DOGE) address = D88gYxMEoumtZSJAC9mwa2EWfm6g3uocon
    Litecoin (LTC) address = LNDYGuiRbA7fHEoidhmgJH8fzqjeseATsU
    Litecoin (LTC) bech32 address = ltc1qyr2956nky56hqr8fuzepdccejse4mw993r7dnr
    Some signs are invisible, some paths are hidden - but those who see, know what to do. Follow the trail - Follow your intuition - [bc1qqnrjshpjpypepxvuagatsqqemnyetsmvzqnafh]

  • jl33213
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    January 20, 2023, 09:44:47 PM
     #2013
    Quote from: Evillo on December 27, 2022, 06:16:27 AM
    Quote from: saxydev on December 26, 2022, 07:48:18 PM
    For half a year I use my cpu to scan for the #67 puzzle. I am 0.000039% scanned addresses of the range ;( A lifetime more to wait. I wonder how many supercomputers out there scan the bitcoin chain for these keys every minute. If you remember the pipeline hack, the FBI had already the privkey for the address used and it was not obtain during a hack or seize.
    But Why the 67th puzzle ?.. why not the easier one? I mean the amount of private keys in 66 is unbelievably enormous already .. why go for the double of that gigantic range?
    because someone is more likely to find 66 before 67 he doesnt wanna spend a shit ton of time on 66 and someone find it before him so he does 67 by time someone does find 66 he will be at head start( to most people anyway ) thats what i think at least

  • Evillo
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    January 21, 2023, 12:40:00 AM
     #2014
    Quote from: jl33213 on January 20, 2023, 09:44:47 PM
    Quote from: Evillo on December 27, 2022, 06:16:27 AM
    Quote from: saxydev on December 26, 2022, 07:48:18 PM
    For half a year I use my cpu to scan for the #67 puzzle. I am 0.000039% scanned addresses of the range ;( A lifetime more to wait. I wonder how many supercomputers out there scan the bitcoin chain for these keys every minute. If you remember the pipeline hack, the FBI had already the privkey for the address used and it was not obtain during a hack or seize.
    But Why the 67th puzzle ?.. why not the easier one? I mean the amount of private keys in 66 is unbelievably enormous already .. why go for the double of that gigantic range?
    because someone is more likely to find 66 before 67 he doesnt wanna spend a shit ton of time on 66 and someone find it before him so he does 67 by time someone does find 66 he will be at head start( to most people anyway ) thats what i think at least

    This analogy may seem smart if we're dealing with normal amounts like million or even billions. But when talking about tens of million trillions, that "head start" gets engulfed to almost nothing. The human mind can't grasp how extremely improbable it is to find ONE address among 73 million trillion ones, let alone double that digit. That being said, why are we still searching?
    Because luck and coincidence do happen. But that's just that, you don't need to try outsmarting your odds in order to land on the key. The only factor you need is luck, and you're surely not doing yourself any more favours by doubling the odds against yourself, aka: puzz 67

  • The_Prof
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    January 21, 2023, 02:50:20 AM
     #2015
    Well in essence, lets say he eventually reaches 0.005 percent when someone hit's 66 on a lucky hit in a year and a bit. if he has large saved segments of what he has searched he can go to tdd/ttd can't remember and say, here are the ranges checked and get his according percentage as was done with 64 when it started. You move from private to a team split. It's the very long game to play. Has it's pro's and cons. 
    Look over there...

  • jl33213
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    January 22, 2023, 08:45:14 PM
     #2016
    Quote from: Evillo on January 21, 2023, 12:40:00 AM
    Quote from: jl33213 on January 20, 2023, 09:44:47 PM
    Quote from: Evillo on December 27, 2022, 06:16:27 AM
    Quote from: saxydev on December 26, 2022, 07:48:18 PM
    For half a year I use my cpu to scan for the #67 puzzle. I am 0.000039% scanned addresses of the range ;( A lifetime more to wait. I wonder how many supercomputers out there scan the bitcoin chain for these keys every minute. If you remember the pipeline hack, the FBI had already the privkey for the address used and it was not obtain during a hack or seize.
    But Why the 67th puzzle ?.. why not the easier one? I mean the amount of private keys in 66 is unbelievably enormous already .. why go for the double of that gigantic range?
    because someone is more likely to find 66 before 67 he doesnt wanna spend a shit ton of time on 66 and someone find it before him so he does 67 by time someone does find 66 he will be at head start( to most people anyway ) thats what i think at least

    This analogy may seem smart if we're dealing with normal amounts like million or even billions. But when talking about tens of million trillions, that "head start" gets engulfed to almost nothing. The human mind can't grasp how extremely improbable it is to find ONE address among 73 million trillion ones, let alone double that digit. That being said, why are we still searching?
    Because luck and coincidence do happen. But that's just that, you don't need to try outsmarting your odds in order to land on the key. The only factor you need is luck, and you're surely not doing yourself any more favours by doubling the odds against yourself, aka: puzz 67

    and im always tryna think of a way to explain that to people you just cant people dont understand cuz its that many numbers lol people who dont know much about btc that is. bitcoins security is literally based on how many numbers it is

  • jl33213
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    January 23, 2023, 06:14:56 AM
     #2017
    Quote from: zahid888 on January 16, 2023, 08:50:52 PM
    Quote from: zahid888 on July 25, 2021, 09:21:39 AM
    @Andzhig And if we increase one more character of address 16jY7qLJn & 'x' then most binaries are started from '111'

    few examples - 

    16jY7qLJnxLQQRYPX5BLuCtcBs6tvXz8BE   1110000000100110101001101101010100100011010011001000100000110110000   7013536A91A6441B0
    16jY7qLJnX9uchnyf26t3QJnsUf78Xdikb   1110010000101000111010000001111110010000001011001101111011100000   E428E81F902CDEE0
    16jY7qLJnX9eX8j612s8fnbn6uzR48xjua   1110100000001101111010110011001110101001011001111010000010001111   E80DEB33A967A08F
    16jY7qLJnx2EZZumnYFke3GutCrRnHKs1M   111010110100110101001101101010111010101000110011101011001010110000   3AD3536AEA8CEB2B0
    16jY7qLJnx2ixrxCnTLSraerkgyB3YYAiT   1110110111111001110011010110000000110101011011011100110000011001   EDF9CD60356DCC19
    16jY7qLJnxHBp3dqwV2kzYq1LucfZzgxsH   1110111010111001101010110011001101001101111100100111011100001101   EEB9AB334DF2770D
    16jY7qLJnX2cZXJ78wV1ef42e7cLAZJ1Vn   1111111000101000011001011100011011011011111111101100001110000011   FE2865C6DBFEC383
    16jY7qLJnxb7CHZyqBP8qca9d51gAjyXQN   1111011100000101000111110010011110110000100100010001001011010100 F7051F27B09112D4


    Could this also be some logic?

    can you shed more light on this issue

    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsreAnchuDf          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU73sVHnoWn
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsreB1FQ8BZ          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU74sHUHy8S
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsreBR6zCMU          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU76rnZwVdz
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsreBbMaQX1          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU77MfhviY5
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsreD437Nay          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7Dq8Au4Pv
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsreGAk6qMH          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7Tmu6qHxS
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsreKD614Nu          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU7hDgvu64y
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsrebwE4gQs          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFU8xvGK1zpm
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsrf5KgGj3x          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUB3vfDKcxZ
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsrfAeGjhSe          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUBTL67V6dE
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsrgQwUiKuq          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUGxXgtm63M
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsrjPKxKjY2          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUW5RtS2JN1
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsrpKArkUBq          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFUspniiQZds
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nEB3kEsrzgDWpY2w          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjgd9M7rFVfZyiN5iEG
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    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4ngeHA7b4zPaJ3ga1          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjidyYKE5NcJQZYvknA
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4nu8VixoNGBCuaLCm          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjjb65nDHeqyjiBaJXv
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4pKxzyzRYGJZF2CUQ          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjqtiAvYTJzYEmqup7b
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4qGMGYDHfP5bxwCnj          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYjv2kTamEYQT9BNC7o1
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip4vCkbw1TKC5xefUVS          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYkHpsTBP19HvTFqiU6i  
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip55U8L18x1xXBdqu84          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYkzijLsc5qE43yZ5eLV
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip59tGc46u8joQDakRT          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYmLDHsih379uP9zbHSD
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip5obPQhDC8LRVrSnwc          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYpCemuaUp7NigjvtJug
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip78q4h8QmfB6MwMuF1          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qYv5Z9J7hv7VYYN3XL3Y
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ip9SbPnb1C74XPPH9cU          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZ6FxoaD5r1kYegmtbaT
    5HpHagT65TZzG1PH3CSu63k8DbpvD8s5ipCnYRNeQuRFKarWVVs          KwDiBf89QgGbjEhKnhXJuH7LrciVrZi3qZM21gaY8WN2CdwnTG57

    for those still doing puzzle:) here is WIF 1-65 compressed and uncompressed hope this helps. if so tip me up bc1q7h54ddkhy7c2fxqvhg34jxejpq89e8k483632a

    i give up now:(

  • digaran
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    January 23, 2023, 08:00:13 AM
     #2018
    Quote from: jl33213 on January 23, 2023, 06:14:56 AM
    for those still doing puzzle:) here is WIF 1-65 compressed and uncompressed hope this helps. if so tip me up.

    i give up now:(
    Why do you have so many uncompressed private keys? Don't you know puzzle transactions use compressed addresses only? Searching for unc addresses and even storing them is a waste of time.
    🖤😏

  • crewchill
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    January 23, 2023, 12:17:04 PM
     #2019
    Code:
    import string
    import random
    import time
    import numpy as np
    import pyopencl as cl 
    import math   
    # You can input here
    length = 17  #hex length for 66
    num = 1000000
    randStr = "abcdefghijklmnopqrstuvwxyz0123456789"

    # end of Input


    def randomwords(size, chars):
    return ''.join(random.choice(chars) for _ in range(size))

    def cpu_gen(length, num, randStr):
    str_list=[]
    cpu_start_time = time.time()  # Get the CPU start time
    for i in range(num):
    str_list.append(randomwords(length, randStr))
    cpu_end_time = time.time()  # Get the CPU end time
    timeGap = cpu_end_time - cpu_start_time
    print("CPU Time: {0} s".format(timeGap))
    print("****************************************************")
    print("Random Strings gnerated by CPU")
    #print(str_list)
    return timeGap

    def gpu_gen(length, num, randStr):
    #define random basic letters
    # radom base length
    totChar = length * num
    randomIndex = len(randStr)
    # parameters of random generation function
    # right_index = np.array.randint(randomIndex, size= totChar)
    right_index = np.empty(totChar, dtype=str)
    ranss = np.array((randStr,))

    rand_seed = math.floor(time.time()) % 20
    # define the contect to use gpu
    ctx = cl.create_some_context(0)
    queue = cl.CommandQueue(ctx)
    # define flag of the opencl
    mf = cl.mem_flags

    rand_buff_1 = cl.Buffer(ctx, mf.READ_ONLY | mf.COPY_HOST_PTR, hostbuf=right_index)
    rand_str = cl.Buffer(ctx, mf.READ_ONLY | mf.COPY_HOST_PTR, hostbuf=ranss)
    program = cl.Program(ctx, """
    int mpow(int n, int p){
    int s =1;
    for(int i=1; i<=p; ++i){
    s = s * n;
    }
    return s;
    }
    int myRand(int next){
    next = ((next * (next % 3) )/50)% 100;
    return next;
    }
    int mabs(int a){
    if (a<0){
    a = 0-a;
    }
    return a;
    }
    int myRandInRange(int next, int min, int max){
    int temp;
    if (max < min){
    temp = max;
    max = min;
    min = temp;
    }
    return myRand(next) % (max + 1 - min) + min;
    }
    __kernel void RandGen(
        __global int *rand_out_buff, __global char *ss, int rand_buff, int seed_buff)
    {
     
      int gid = get_global_id(0);

      int temp = mpow(gid, seed_buff) + seed_buff % (gid+1);
     
      int input = myRandInRange(temp, gid * seed_buff, gid * (gid % seed_buff)) + seed_buff;
      input  = mabs(input);
      rand_out_buff[gid] =ss[(input % rand_buff)*4];
    }
    """).build()

    rand_out_buff = cl.Buffer(ctx, mf.WRITE_ONLY, right_index.nbytes)
    gpu_start_time = time.time()
    event = program.RandGen(queue, right_index.shape, None, rand_out_buff, rand_str, np.int32(randomIndex), np.int32(rand_seed))
    event.wait()
    rand_list = np.empty_like(right_index)
    cl.enqueue_copy(queue, rand_list, rand_out_buff)
    gpu_end_time = time.time()  # Get the GPU end time
    timeGap = gpu_end_time - gpu_start_time
    print("GPU Time: {0} s".format(timeGap))
    for i in range(totChar):
    if i>1 and i % length==0:print('' ,end='')
    #print(rand_list[i], end='')
    #print('')
    print("****************************************************")
    print("Random Strings gnerated by GPU")
    return timeGap

    cpu_time = cpu_gen(length, num, randStr)
    gpu_time = gpu_gen(length, num, randStr)
    print("****************************************************")
    print("CPU and GPU execution time comparison")
    print("CPU Time: {0} s".format(cpu_time))
    print("GPU Time: {0} s".format(gpu_time))


     compile this random generator with  ice.secp256k1 to increase speed.

  • citb0in
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    January 23, 2023, 12:32:48 PM
     #2020
    Quote from: crewchill on January 23, 2023, 12:17:04 PM
    Code:
    [...]
    num = 50000000
    [...]
    #cpu_time = cpu_gen(length, num, randStr)
    gpu_time = gpu_gen(length, num, randStr)
    print("****************************************************")
    print("CPU and GPU execution time comparison")
    #print("CPU Time: {0} s".format(cpu_time))
    print("GPU Time: {0} s".format(gpu_time))

    I was curious to see if and how fast the GPU part is done. So I disabled the CPU part in your code and raised num to 50 million. Before starting I opened my Nvidia System app to monitor the load of my GPU. After about 1.5 sec my Nvidia System Monitor showed
    Quote
    Used Dedicated Memory: 3531 MB (43%)
    GPU Utilization: 0%

    that means that data was loaded into the dedicated memory, but GPU utilization remains during the complete run at 0% which is unusual. Whenever I run other tools like VanitySearch, BitCrack, KeyHunt-Cuda, etc. GPU utilization is at 100%. I doubt that everything is running at optimum speed inside the GPU part.

    Also, when measuring the execution time it takes 39sec. and not only 0.9sec as stated by the program.

    Quote
    $ time python3 crewchill.py
    GPU Time: 0.9311995506286621 s
    ****************************************************
    Random Strings gnerated by GPU
    ****************************************************
    CPU and GPU execution time comparison
    GPU Time: 0.9311995506286621 s

    real   0m39,594s
    user   0m38,058s
    sys   0m3,153s
    Some signs are invisible, some paths are hidden - but those who see, know what to do. Follow the trail - Follow your intuition - [bc1qqnrjshpjpypepxvuagatsqqemnyetsmvzqnafh]
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