bc1qtgttq2pn4alt8sfdll5nhwyjj4w24hm5ulv0hw

Thanks.

WELCOME!
bc1qulqzymg4v2gqqvxsc6mnr4npywswqcyfm3rzgq

Let's see how lucky I am

bc1q293606en2aruadrk3lpsme5pmggzmr2aerw58n

Thanks in advance.

bc1qus6v2ty0nn2lfghxvq5zwc4jf9em3w4zh566e3
Thanks

bc1qm9n4ylpa9ddf7j2q87jjyt9vuzq7mx3lf4cx85


ty

We should have the answer tomorrow 

I'll be rolling it soon, any idea how to roll it, i want to be as much as transparent as I can

To expand on this to help you with compiling the list Rbah, here are the first 3 participants compiled in a format that you can use continue on to do the whole list of entrants.

[10] TheChin0s bc1qnn44lgfzmzl3kk68gccdke4z6vxgwju272nsss
[11] GazetaBitcoin bc1qgfluvq03jcqzvaz6dc00qqgvyvmfuxra6etsd2
[12] CoinEraser bc1q4v2e08evleg047rcfnea97rampclqqzp682pgg 


If you're wondering how xLays got 92:
00000000000000000002f4a304f5939bc22e379a208b2b977fd84021d8cb59e2 is the winning hash. 9e2 are the last parts of the hash. Remove the "e" and you get 92.

The reason for the list starting at [10], is if the result the hash is 9e2 like above and you've started counting entrants between 1 and 10, the winner is both [2] and [92]. Starting at 10 should stop you from facing that problem.

I am not sure if you are making fun or you really believe that you won therefore, for making sure that no confusion goes from here, you did not win anything yet. xLays was merely giving OP an example of how to pick the last two numbers of the block hash.


And, in that example, you were the winner. But it was just an example.

Furthermore, as far as I know, bitmover is looking for a solution of choosing the winner. Unless something clear comes up, please wait for an official roll to be made.