As previously mentioned, I have a total of 588 ranges, where is a private key of puzzle 66. Each range requires a 48-bit computation (I am referring to GPU computation). and I am seeking an individual who is capable of performing these computations within few minutes or at least an hour.

As for our collaboration approach, I am currently developing a script to scan all 588 ranges. Once the private key is obtained, the script will automatically perform the following actions: 2% of the amount will be deducted as fees, 59% will be sent to the individual performing the computations, and 39% will be sent to me. my bitcoin address and the computation performer's bitcoin address will be pre-entered into the script. The reason for allocating 59% to the computation performer is due to their resource usage, whether through GPU rental or electricity consumption. I intend to share the entire script with the individual to ensure transparency, while keeping the ranges known only to me. Once the script initiates, neither of us will have any access to it. But when scanning of one range completed, it will be saved along with the proof of work. Certainly, it will take me some time to perform all these processes.

So why not continue searching for that person in the meantime?

---

(This range is an example of 588 ranges: 3b07a000000000000:3b07affffffffffff, and this address is for proof of work: 1GYpdGZBaqRDKkpFWbaRezrVeGy6g6UNfE, 1Ngdkik5LLGzmzYUWKiPYDQ6CRRGWCPo5L, 19XbiMqyqeaJLDSvHLzhJkxngDYsBPXTQo, 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so)

---

The person who will perform the counting of this range needs to be scanned and to post here with proof of work, or they can personally DM me as well.  In this interaction, I will assess their operational speed in completing this 48-bit range. For scanning, they can use any software, but my suggestion is to use 'VanBitCrackenS v1.0' because here they can take advantage of multi-GPU. If the puzzle address falls within this range, then it will be yours. 👍

Download and run this java calculator, it's very slow and heavy but it's good for manual calculations which is why you can only do manual calc with it.
https://github.com/MrMaxweII/Secp256k1-Calculator

Select scalar on both sides, and place private keys in hex format, then select * , + , - , ÷ , and see for yourself what would be the result.

What you should consider when dividing an odd key, dividing any odd key by 2 will always give you .5 ( point 5, half ), anything on the left side of the point . Is your actuall result no matter if you are dividing by 2 or any other number, but for example we use 2, and anything on the right side of the point . Is a 2^255 + key, we don't want that, so we subtract that from our result to get the actual answer.

3 divided by 2 = 1.>5 <  this 5 here means half of n, so if we subtract it from 1.5, we will get 1, our actual result.

Now lets make it a bit difficult, let us divide 7 by 3 = 2.33333333333333333333333333333333333333333333333333333333333333333333333333333 3333333333333333333333333333333333333333333333333333333333333333333333333333333 3333333333333333333333333333333333333333333

Now to get the n/33333........... more 333333..... etc, no need to do any complicated calculation, we just divide 7 by 3 mod n to quickly get the result, then we subtract it from the result to get our key.

---

Never mind all the above, I have something to twist your minds, take the following key and double, divide, do many other things with it to get really confused about how EC works. 😂

Introducing to you 2^256 of secp256k1


Try multiplying it by 2, 3, 4, 5 etc as well as dividing it, this little sucker is hiding it's half under the ground!

As previously mentioned, I have a total of 588 ranges, where is a private key of puzzle 66. Each range requires a 48-bit computation (I am referring to GPU computation). and I am seeking an individual who is capable of performing these computations within few minutes or at least an hour.

As for our collaboration approach, I am currently developing a script to scan all 588 ranges. Once the private key is obtained, the script will automatically perform the following actions: 2% of the amount will be deducted as fees, 59% will be sent to the individual performing the computations, and 39% will be sent to me. my bitcoin address and the computation performer's bitcoin address will be pre-entered into the script. The reason for allocating 59% to the computation performer is due to their resource usage, whether through GPU rental or electricity consumption. I intend to share the entire script with the individual to ensure transparency, while keeping the ranges known only to me. Once the script initiates, neither of us will have any access to it. But when scanning of one range completed, it will be saved along with the proof of work. Certainly, it will take me some time to perform all these processes.

So why not continue searching for that person in the meantime?

---

(This range is an example of 588 ranges: 3b07a000000000000:3b07affffffffffff, and this address is for proof of work: 1GYpdGZBaqRDKkpFWbaRezrVeGy6g6UNfE, 1Ngdkik5LLGzmzYUWKiPYDQ6CRRGWCPo5L, 19XbiMqyqeaJLDSvHLzhJkxngDYsBPXTQo, 13zb1hQbWVsc2S7ZTZnP2G4undNNpdh5so)

---

The person who will perform the counting of this range needs to be scanned and to post here with proof of work, or they can personally DM me as well.  In this interaction, I will assess their operational speed in completing this 48-bit range. For scanning, they can use any software, but my suggestion is to use 'VanBitCrackenS v1.0' because here they can take advantage of multi-GPU. If the puzzle address falls within this range, then it will be yours. 👍

Thanks for the info bro. I use this calculator, it works great! And how do we subtract half of n from the point X and Y coordinates?, or do we need to get the coordinates x, y from half of n? (if there is, then what are the coordinates of half of n). Or was the subtraction just an example to show so that I would understand?.

OK, tomorrow I'll try to test this key))

-snip-
"3PdQoXyQwWmerpt3SbF7Hbh3aukXXXXXXX" P2SH ( sorry if i do "X" end address, it might be easier to cashout when you can do something with this main/test net addresses.

WHO KNOWS THE PUBLIC KEY 66? I CAN EVEN FIND THE P2SH ADDRESS, HAHA!  

Hi, so  i found 2 address similar 11 digits of hash160 in extraction of bit 130 that means if you scan on this range and have the private key of those one of two addresses we will split the 13 BTC
---SNIP---

This phase of learning, I call it kindergarten phase, I have also passed this era, I'm in preschool now. Lol.

They need to learn their lessons through experience if verbal education is  not effective.
😉

so i stop posting new things

im helping the community to solve the puzzle at least im doing something and sharing something

and im not like you always ask for help and how to do that

and never did give us something that help solving this puzzle.