You missed the last part where I criticized your sample size for being too small.

Edit:  Although, I do like this math.  It's fun for me and my favorite baseball team.  Based on yesterday's results (big enough sample size for most everyone that is arguing difficulty here, no?)  My Rangers are going to average 1.78 runs every inning for the rest of the year.  World Series here we come baby!

I am still staying out of this converstaion as I REALLY dont understand it all..

But one thing someone said a few pages back that I did not understand that I would like to understand is someone said something like H20 dont care as he will make the same no matter what..  What does that mean exactly?     Is not what H20 makes based on what we make and if we make more he makes more?

Lower your scantime in cgminer

Regardless of difficulty, what pays all of the miners and the pool operator is the number of blocks found.

Miners are paid out based of succesful shares of the found blocks.  Whether Miner A gets 70% shares and Miner B gets 30% shares or any other combination, Pool Op still gets fees on all 100% shares.  His profit is only affected by the total hashrate and the market depth that determines which coins are the most profitable.

As I stated before, the thing more important than changing the difficulty (as I don't see how this affects the pool overall) is finding a way to divert hashrate to multiple coins to take advantage of coins with smaller, but profitable, market depth on their perspective market.

So i took my work on my spreadsheet and put it into a single formula.. then i realized... Its WAY simpler than all of that makes it seem.

Given a particular diff rate and difficulty, and the values of x and y that result from that:

If:

X = Average time for miner to find a share

Y = Average block find time


x/2*y = Percentage of LOST profit/hashpower


It's really as simple as that.

The solution is as simple as lowering X. How do you lower X? Lower difficulty.


Edit: Forgot the2 part, because you'll be at a random point of progress on the share each time a block changes, averaging to half complete

I guess that's what I don't understand.  

Instead of average block time, wouldn't it make more sense to use total time that xCoin is mined?  

If we are only on a coin for 20 seconds and you only find a share every minute, then it makes sense that you won't expect to earn any shares.  However, if the average block time is 1s (or 30s or 1m) but we mine the coin for an hour, shouldn't you still be expected to get 60 shares in that hour?

That's not addressing what I don't understand though.

If we find a block in a minute, we don't necessarily move to another coin. 

IF MinerAvgShareTime > CoinMiningTime THEN Profit = Lost
IF MinerAvgShareTime < CoinMiningTime THEN Profit = Gained

Are there many instances where we are only mining a specific coin for a minute or two?  I haven't paid close attention to the total duration of each specific coins, but I've been pleased with the overall results of this pool and my hashrate is less than 1MH/s

Ok, i see what you are confused on.

We keep talking about when we change blocks, but the same thing happens when we switch coins, too. Its just that since that happens much much less, and is part of the secret formula of the pool, its not worth mentioning really. Yet, lowering diff helps optimize it just the same way.

Without seeing the secret sauce, the best way to tell if we switch coins is to just listen to your cards throttle down. I don't think it happens too often, maybe 5-10 minutes sometimes but I am just guessing... i know I have been in my office for hours and not heard it before as well.

So then wouldn't it mean that as long as your average share time was under 5-10 minutes then the difficulty would not affect anything?